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131005415035 = 5112381916637
BaseRepresentation
bin111101000000010000…
…1111111111001111011
3110112010222210121202201
41322000201333321323
54121244341240120
6140103312411031
712315302440345
oct1720041777173
9415128717681
10131005415035
1150617161350
1221481546a77
13c47a289681
1464aac26295
15361b26440a
hex1e8087fe7b

131005415035 has 8 divisors (see below), whose sum is σ = 171497997936. Its totient is φ = 95276665440.

The previous prime is 131005414997. The next prime is 131005415039. The reversal of 131005415035 is 530514500131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131005415035 - 27 = 131005414907 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131005414994 and 131005415012.

It is not an unprimeable number, because it can be changed into a prime (131005415039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1190958264 + ... + 1190958373.

It is an arithmetic number, because the mean of its divisors is an integer number (21437249742).

Almost surely, 2131005415035 is an apocalyptic number.

131005415035 is a deficient number, since it is larger than the sum of its proper divisors (40492582901).

131005415035 is a wasteful number, since it uses less digits than its factorization.

131005415035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2381916653.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 131005415035 its reverse (530514500131), we get a palindrome (661519915166).

The spelling of 131005415035 in words is "one hundred thirty-one billion, five million, four hundred fifteen thousand, thirty-five".

Divisors: 1 5 11 55 2381916637 11909583185 26201083007 131005415035