131010210331403 has 4 divisors (see below), whose sum is σ = 141087918818448. Its totient is φ = 120932501844360.

The previous prime is 131010210331381. The next prime is 131010210331417. The reversal of 131010210331403 is 304133012010131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131010210331403 is a prime.

It is a super-2 number, since 2×131010210331403² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131010210331423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5038854243503 + ... + 5038854243528.

It is an arithmetic number, because the mean of its divisors is an integer number (35271979704612).

Almost surely, 2^{131010210331403} is an apocalyptic number.

131010210331403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

131010210331403 is a deficient number, since it is larger than the sum of its proper divisors (10077708487045).

131010210331403 is a wasteful number, since it uses less digits than its factorization.

131010210331403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10077708487044.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 131010210331403 its reverse (304133012010131), we get a palindrome (435143222341534).

The spelling of 131010210331403 in words is "one hundred thirty-one trillion, ten billion, two hundred ten million, three hundred thirty-one thousand, four hundred three".