13101023341121 has 4 divisors (see below), whose sum is σ = 13110191308500. Its totient is φ = 13091855373744.

The previous prime is 13101023341067. The next prime is 13101023341129. The reversal of 13101023341121 is 12114332010131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2834997225025 + 10266026116096 = 1683745^2 + 3204064^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101023341121 - 2³⁸ = 12826145434177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101023341129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4583981546 + ... + 4583984403.

It is an arithmetic number, because the mean of its divisors is an integer number (3277547827125).

Almost surely, 2^{13101023341121} is an apocalyptic number.

It is an amenable number.

13101023341121 is a deficient number, since it is larger than the sum of its proper divisors (9167967379).

13101023341121 is an equidigital number, since it uses as much as digits as its factorization.

13101023341121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9167967378.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13101023341121 its reverse (12114332010131), we get a palindrome (25215355351252).

The spelling of 13101023341121 in words is "thirteen trillion, one hundred one billion, twenty-three million, three hundred forty-one thousand, one hundred twenty-one".