1310103210113 has 4 divisors (see below), whose sum is σ = 1317422222640. Its totient is φ = 1302784197588.

The previous prime is 1310103210047. The next prime is 1310103210133. The reversal of 1310103210113 is 3110123010131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310103210113 - 2¹⁰ = 1310103209089 is a prime.

It is a super-2 number, since 2×1310103210113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310103210091 and 1310103210100.

It is not an unprimeable number, because it can be changed into a prime (1310103210133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3659505995 + ... + 3659506352.

It is an arithmetic number, because the mean of its divisors is an integer number (329355555660).

Almost surely, 2^{1310103210113} is an apocalyptic number.

It is an amenable number.

1310103210113 is a deficient number, since it is larger than the sum of its proper divisors (7319012527).

1310103210113 is an equidigital number, since it uses as much as digits as its factorization.

1310103210113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7319012526.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1310103210113 its reverse (3110123010131), we get a palindrome (4420226220244).

The spelling of 1310103210113 in words is "one trillion, three hundred ten billion, one hundred three million, two hundred ten thousand, one hundred thirteen".