Search a number
-
+
131010333203 = 131581995663
BaseRepresentation
bin111101000000011010…
…0110000101000010011
3110112011100001111020002
41322000310300220103
54121302121130303
6140104010040215
712315362313131
oct1720064605023
9415140044202
10131010333203
1150619a10452
122148311906b
13c47b2bc129
1464ab746751
15361b8d6788
hex1e80d30a13

131010333203 has 4 divisors (see below), whose sum is σ = 131011460448. Its totient is φ = 131009205960.

The previous prime is 131010333173. The next prime is 131010333239. The reversal of 131010333203 is 302333010131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 131010333203 - 216 = 131010267667 is a prime.

It is a super-2 number, since 2×1310103332032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131010333263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 366251 + ... + 629412.

It is an arithmetic number, because the mean of its divisors is an integer number (32752865112).

Almost surely, 2131010333203 is an apocalyptic number.

131010333203 is a deficient number, since it is larger than the sum of its proper divisors (1127245).

131010333203 is an equidigital number, since it uses as much as digits as its factorization.

131010333203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1127244.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 131010333203 its reverse (302333010131), we get a palindrome (433343343334).

The spelling of 131010333203 in words is "one hundred thirty-one billion, ten million, three hundred thirty-three thousand, two hundred three".

Divisors: 1 131581 995663 131010333203