131011120240403 has 4 divisors (see below), whose sum is σ = 141088898720448. Its totient is φ = 120933341760360.

The previous prime is 131011120240331. The next prime is 131011120240439. The reversal of 131011120240403 is 304042021110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131011120240403 - 2¹⁰ = 131011120239379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131011120240103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5038889240003 + ... + 5038889240028.

It is an arithmetic number, because the mean of its divisors is an integer number (35272224680112).

Almost surely, 2^{131011120240403} is an apocalyptic number.

131011120240403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

131011120240403 is a deficient number, since it is larger than the sum of its proper divisors (10077778480045).

131011120240403 is a wasteful number, since it uses less digits than its factorization.

131011120240403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10077778480044.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131011120240403 its reverse (304042021110131), we get a palindrome (435053141350534).

The spelling of 131011120240403 in words is "one hundred thirty-one trillion, eleven billion, one hundred twenty million, two hundred forty thousand, four hundred three".