131011124130041 has 4 divisors (see below), whose sum is σ = 131011198180752. Its totient is φ = 131011050079332.

The previous prime is 131011124130001. The next prime is 131011124130049. The reversal of 131011124130041 is 140031421110131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131011124130041 - 2²² = 131011119935737 is a prime.

It is a super-2 number, since 2×131011124130041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131011124129989 and 131011124130016.

It is not an unprimeable number, because it can be changed into a prime (131011124130049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34304915 + ... + 37932168.

It is an arithmetic number, because the mean of its divisors is an integer number (32752799545188).

Almost surely, 2^{131011124130041} is an apocalyptic number.

It is an amenable number.

131011124130041 is a deficient number, since it is larger than the sum of its proper divisors (74050711).

131011124130041 is an equidigital number, since it uses as much as digits as its factorization.

131011124130041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74050710.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 131011124130041 its reverse (140031421110131), we get a palindrome (271042545240172).

The spelling of 131011124130041 in words is "one hundred thirty-one trillion, eleven billion, one hundred twenty-four million, one hundred thirty thousand, forty-one".