13101121220233 has 4 divisors (see below), whose sum is σ = 13101129300240. Its totient is φ = 13101113140228.

The previous prime is 13101121220203. The next prime is 13101121220273. The reversal of 13101121220233 is 33202212110131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13101121220233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101121220203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 671863 + ... + 5162716.

It is an arithmetic number, because the mean of its divisors is an integer number (3275282325060).

Almost surely, 2^{13101121220233} is an apocalyptic number.

It is an amenable number.

13101121220233 is a deficient number, since it is larger than the sum of its proper divisors (8080007).

13101121220233 is an equidigital number, since it uses as much as digits as its factorization.

13101121220233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8080006.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13101121220233 its reverse (33202212110131), we get a palindrome (46303333330364).

The spelling of 13101121220233 in words is "thirteen trillion, one hundred one billion, one hundred twenty-one million, two hundred twenty thousand, two hundred thirty-three".