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1310130043211 = 11119102731201
BaseRepresentation
bin10011000100001001110…
…101011111100101001011
311122020200012210222002202
4103010021311133211023
5132431121242340321
62441510533350415
7163440146424143
oct23041165374513
94566605728082
101310130043211
11465694288630
12191ab3a9840b
1396710a16c52
14475a6abd923
152412d41e70b
hex13109d5f94b

1310130043211 has 4 divisors (see below), whose sum is σ = 1429232774424. Its totient is φ = 1191027312000.

The previous prime is 1310130043199. The next prime is 1310130043231. The reversal of 1310130043211 is 1123400310131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310130043211 - 210 = 1310130042187 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310130043231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59551365590 + ... + 59551365611.

It is an arithmetic number, because the mean of its divisors is an integer number (357308193606).

Almost surely, 21310130043211 is an apocalyptic number.

1310130043211 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1310130043211 is a deficient number, since it is larger than the sum of its proper divisors (119102731213).

1310130043211 is a wasteful number, since it uses less digits than its factorization.

1310130043211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119102731212.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1310130043211 its reverse (1123400310131), we get a palindrome (2433530353342).

The spelling of 1310130043211 in words is "one trillion, three hundred ten billion, one hundred thirty million, forty-three thousand, two hundred eleven".

Divisors: 1 11 119102731201 1310130043211