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13101302011331 = 24235407058197
BaseRepresentation
bin1011111010100110001001…
…1100111101010111000011
31201101110202021002220022002
42332221202130331113003
53204122431303330311
643510353254134215
72521352322445322
oct276514234752703
951343667086262
1013101302011331
1141a125a487216
12157715365136b
137405a8158461
1433416bd6c0b9
1517abdcd5c93b
hexbea6273d5c3

13101302011331 has 4 divisors (see below), whose sum is σ = 13106709071952. Its totient is φ = 13095894950712.

The previous prime is 13101302011327. The next prime is 13101302011367. The reversal of 13101302011331 is 13311020310131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101302011331 - 22 = 13101302011327 is a prime.

It is a super-3 number, since 3×131013020113313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13101302001331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2703526676 + ... + 2703531521.

It is an arithmetic number, because the mean of its divisors is an integer number (3276677267988).

Almost surely, 213101302011331 is an apocalyptic number.

13101302011331 is a deficient number, since it is larger than the sum of its proper divisors (5407060621).

13101302011331 is an equidigital number, since it uses as much as digits as its factorization.

13101302011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5407060620.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 13101302011331 its reverse (13311020310131), we get a palindrome (26412322321462).

The spelling of 13101302011331 in words is "thirteen trillion, one hundred one billion, three hundred two million, eleven thousand, three hundred thirty-one".

Divisors: 1 2423 5407058197 13101302011331