1310131112131 has 4 divisors (see below), whose sum is σ = 1318807477264. Its totient is φ = 1301454747000.

The previous prime is 1310131112089. The next prime is 1310131112183. The reversal of 1310131112131 is 1312111310131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310131112131 - 2¹⁵ = 1310131079363 is a prime.

It is a super-2 number, since 2×1310131112131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310131112099 and 1310131112108.

It is not an unprimeable number, because it can be changed into a prime (1310131119131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4338182340 + ... + 4338182641.

It is an arithmetic number, because the mean of its divisors is an integer number (329701869316).

Almost surely, 2^{1310131112131} is an apocalyptic number.

1310131112131 is a deficient number, since it is larger than the sum of its proper divisors (8676365133).

1310131112131 is an equidigital number, since it uses as much as digits as its factorization.

1310131112131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8676365132.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 1310131112131 its reverse (1312111310131), we get a palindrome (2622242422262).

The spelling of 1310131112131 in words is "one trillion, three hundred ten billion, one hundred thirty-one million, one hundred twelve thousand, one hundred thirty-one".