13101312113 has 4 divisors (see below), whose sum is σ = 13121688048. Its totient is φ = 13080936180.

The previous prime is 13101312073. The next prime is 13101312139. The reversal of 13101312113 is 31121310131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121310131 = 11047 ⋅2817173.

It is a cyclic number.

It is not a de Polignac number, because 13101312113 - 2¹⁰ = 13101311089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101312091 and 13101312100.

It is not an unprimeable number, because it can be changed into a prime (13101312143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10187003 + ... + 10188288.

It is an arithmetic number, because the mean of its divisors is an integer number (3280422012).

Almost surely, 2^13101312113 is an apocalyptic number.

It is an amenable number.

13101312113 is a deficient number, since it is larger than the sum of its proper divisors (20375935).

13101312113 is an equidigital number, since it uses as much as digits as its factorization.

13101312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20375934.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13101312113 its reverse (31121310131), we get a palindrome (44222622244).

The spelling of 13101312113 in words is "thirteen billion, one hundred one million, three hundred twelve thousand, one hundred thirteen".