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131014241433 = 3215196404887
BaseRepresentation
bin111101000000100001…
…1101010110010011001
3110112011121102001022100
41322001003222302121
54121304121211213
6140104225514013
712315440451315
oct1720103526231
9415147361270
10131014241433
115062113a799
12214844a2909
13c47c059caa
1464ac082b45
15361be09773
hex1e810eac99

131014241433 has 12 divisors (see below), whose sum is σ = 190496058688. Its totient is φ = 86764397400.

The previous prime is 131014241419. The next prime is 131014241437. The reversal of 131014241433 is 334142410131.

It is not a de Polignac number, because 131014241433 - 218 = 131013979289 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131014241397 and 131014241406.

It is not an unprimeable number, because it can be changed into a prime (131014241437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 48201085 + ... + 48203802.

Almost surely, 2131014241433 is an apocalyptic number.

It is an amenable number.

131014241433 is a deficient number, since it is larger than the sum of its proper divisors (59481817255).

131014241433 is a wasteful number, since it uses less digits than its factorization.

131014241433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96405044 (or 96405041 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 131014241433 its reverse (334142410131), we get a palindrome (465156651564).

The spelling of 131014241433 in words is "one hundred thirty-one billion, fourteen million, two hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 3 9 151 453 1359 96404887 289214661 867643983 14557137937 43671413811 131014241433