1310143014041 has 4 divisors (see below), whose sum is σ = 1340611456272. Its totient is φ = 1279674571812.

The previous prime is 1310143014031. The next prime is 1310143014073. The reversal of 1310143014041 is 1404103410131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310143014041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1310143013998 and 1310143014016.

It is not an unprimeable number, because it can be changed into a prime (1310143014031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15234221051 + ... + 15234221136.

It is an arithmetic number, because the mean of its divisors is an integer number (335152864068).

Almost surely, 2^{1310143014041} is an apocalyptic number.

It is an amenable number.

1310143014041 is a deficient number, since it is larger than the sum of its proper divisors (30468442231).

1310143014041 is an equidigital number, since it uses as much as digits as its factorization.

1310143014041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30468442230.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1310143014041 its reverse (1404103410131), we get a palindrome (2714246424172).

The spelling of 1310143014041 in words is "one trillion, three hundred ten billion, one hundred forty-three million, fourteen thousand, forty-one".