Base | Representation |
---|---|
bin | 11000011001110100… |
… | …11010101100000001 |
3 | 1020211001212022002200 |
4 | 30030322122230001 |
5 | 203312443322040 |
6 | 10004015303413 |
7 | 642445161606 |
oct | 141472325401 |
9 | 36731768080 |
10 | 13101542145 |
11 | 561352a58a |
12 | 265781ab69 |
13 | 130a435403 |
14 | 8c403c6ad |
15 | 51a30d630 |
hex | 30ce9ab01 |
13101542145 has 12 divisors (see below), whose sum is σ = 22709339796. Its totient is φ = 6987489120.
The previous prime is 13101542107. The next prime is 13101542189. The reversal of 13101542145 is 54124510131.
13101542145 is a `hidden beast` number, since 1 + 3 + 101 + 542 + 14 + 5 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 8750292849 + 4351249296 = 93543^2 + 65964^2 .
It is not a de Polignac number, because 13101542145 - 26 = 13101542081 is a prime.
It is a super-2 number, since 2×131015421452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 145572646 + ... + 145572735.
It is an arithmetic number, because the mean of its divisors is an integer number (1892444983).
Almost surely, 213101542145 is an apocalyptic number.
13101542145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13101542145 is a deficient number, since it is larger than the sum of its proper divisors (9607797651).
13101542145 is a wasteful number, since it uses less digits than its factorization.
13101542145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 291145392 (or 291145389 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
The spelling of 13101542145 in words is "thirteen billion, one hundred one million, five hundred forty-two thousand, one hundred forty-five".
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