13102001113 has 4 divisors (see below), whose sum is σ = 13102352128. Its totient is φ = 13101650100.

The previous prime is 13102001071. The next prime is 13102001149. The reversal of 13102001113 is 31110020131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13102001113 - 2²¹ = 13099903961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13102001093 and 13102001102.

It is not an unprimeable number, because it can be changed into a prime (13102001153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111813 + ... + 196738.

It is an arithmetic number, because the mean of its divisors is an integer number (3275588032).

Almost surely, 2^13102001113 is an apocalyptic number.

It is an amenable number.

13102001113 is a deficient number, since it is larger than the sum of its proper divisors (351015).

13102001113 is an equidigital number, since it uses as much as digits as its factorization.

13102001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 351014.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 13102001113 its reverse (31110020131), we get a palindrome (44212021244).

The spelling of 13102001113 in words is "thirteen billion, one hundred two million, one thousand, one hundred thirteen".