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131020022010201 = 343673340670067
BaseRepresentation
bin11101110010100101111001…
…110111101101000101011001
3122011220101120121101012211020
4131302211321313231011121
5114133113001113311301
61142353433413353053
736411612166555212
oct3562457167550531
9564811517335736
10131020022010201
1138824308815795
1212840684338789
13581519a963a2c
14244d58d7ba409
1510231e8977436
hex772979ded159

131020022010201 has 4 divisors (see below), whose sum is σ = 174693362680272. Its totient is φ = 87346681340132.

The previous prime is 131020022010181. The next prime is 131020022010203. The reversal of 131020022010201 is 102010220020131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131020022010201 - 25 = 131020022010169 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131020022010203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21836670335031 + ... + 21836670335036.

It is an arithmetic number, because the mean of its divisors is an integer number (43673340670068).

Almost surely, 2131020022010201 is an apocalyptic number.

It is an amenable number.

131020022010201 is a deficient number, since it is larger than the sum of its proper divisors (43673340670071).

131020022010201 is an equidigital number, since it uses as much as digits as its factorization.

131020022010201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43673340670070.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 131020022010201 its reverse (102010220020131), we get a palindrome (233030242030332).

The spelling of 131020022010201 in words is "one hundred thirty-one trillion, twenty billion, twenty-two million, ten thousand, two hundred one".

Divisors: 1 3 43673340670067 131020022010201