1310202021113 has 4 divisors (see below), whose sum is σ = 1310260272228. Its totient is φ = 1310143770000.

The previous prime is 1310202021061. The next prime is 1310202021133. The reversal of 1310202021113 is 3111202020131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 970437771664 + 339764249449 = 985108^2 + 582893^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310202021113 - 2²² = 1310197826809 is a prime.

It is a super-2 number, since 2×1310202021113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310202021091 and 1310202021100.

It is not an unprimeable number, because it can be changed into a prime (1310202021133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29091806 + ... + 29136807.

It is an arithmetic number, because the mean of its divisors is an integer number (327565068057).

Almost surely, 2^{1310202021113} is an apocalyptic number.

It is an amenable number.

1310202021113 is a deficient number, since it is larger than the sum of its proper divisors (58251115).

1310202021113 is an equidigital number, since it uses as much as digits as its factorization.

1310202021113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58251114.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1310202021113 its reverse (3111202020131), we get a palindrome (4421404041244).

The spelling of 1310202021113 in words is "one trillion, three hundred ten billion, two hundred two million, twenty-one thousand, one hundred thirteen".