131020240314011 has 4 divisors (see below), whose sum is σ = 132598797426312. Its totient is φ = 129441683201712.

The previous prime is 131020240314001. The next prime is 131020240314031. The reversal of 131020240314011 is 110413042020131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131020240314011 - 2¹⁰ = 131020240312987 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131020240314001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 789278556026 + ... + 789278556191.

It is an arithmetic number, because the mean of its divisors is an integer number (33149699356578).

Almost surely, 2^{131020240314011} is an apocalyptic number.

131020240314011 is a deficient number, since it is larger than the sum of its proper divisors (1578557112301).

131020240314011 is an equidigital number, since it uses as much as digits as its factorization.

131020240314011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1578557112300.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131020240314011 its reverse (110413042020131), we get a palindrome (241433282334142).

The spelling of 131020240314011 in words is "one hundred thirty-one trillion, twenty billion, two hundred forty million, three hundred fourteen thousand, eleven".