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13102030003 = 37354108919
BaseRepresentation
bin11000011001111000…
…10001110010110011
31020211002210002022111
430030330101302303
5203313104430003
610004033550151
7642452263126
oct141474216263
936732702274
1013102030003
115613833077
122657a15357
13130a57649a
148c41283bd
1551a3a7e6d
hex30cf11cb3

13102030003 has 4 divisors (see below), whose sum is σ = 13456138960. Its totient is φ = 12747921048.

The previous prime is 13102029991. The next prime is 13102030021. The reversal of 13102030003 is 30003020131.

13102030003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13102030003 - 225 = 13068475571 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102030103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177054423 + ... + 177054496.

It is an arithmetic number, because the mean of its divisors is an integer number (3364034740).

Almost surely, 213102030003 is an apocalyptic number.

13102030003 is a deficient number, since it is larger than the sum of its proper divisors (354108957).

13102030003 is an equidigital number, since it uses as much as digits as its factorization.

13102030003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354108956.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 13102030003 its reverse (30003020131), we get a palindrome (43105050134).

The spelling of 13102030003 in words is "thirteen billion, one hundred two million, thirty thousand, three".

Divisors: 1 37 354108919 13102030003