Base | Representation |
---|---|
bin | 11101110010100110010010… |
… | …010111100001001110110011 |
3 | 122011220102122020201211120011 |
4 | 131302212102113201032303 |
5 | 114133114321322102233 |
6 | 1142353542254355351 |
7 | 36411625320134224 |
oct | 3562462227411663 |
9 | 564812566654504 |
10 | 131020433003443 |
11 | 388244a980a025 |
12 | 12840779abbb57 |
13 | 5815234b53cb9 |
14 | 244d5cc20324b |
15 | 102321eaad0cd |
hex | 7729925e13b3 |
131020433003443 has 8 divisors (see below), whose sum is σ = 132065008563312. Its totient is φ = 129979690749216.
The previous prime is 131020433003417. The next prime is 131020433003459. The reversal of 131020433003443 is 344300334020131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131020433003443 - 225 = 131020399449011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131020433003543) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 958257780 + ... + 958394497.
It is an arithmetic number, because the mean of its divisors is an integer number (16508126070414).
Almost surely, 2131020433003443 is an apocalyptic number.
131020433003443 is a deficient number, since it is larger than the sum of its proper divisors (1044575559869).
131020433003443 is a wasteful number, since it uses less digits than its factorization.
131020433003443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1916652821.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 131020433003443 its reverse (344300334020131), we get a palindrome (475320767023574).
The spelling of 131020433003443 in words is "one hundred thirty-one trillion, twenty billion, four hundred thirty-three million, three thousand, four hundred forty-three".
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