Base | Representation |
---|---|
bin | 1011111010101001001000… |
… | …0001011110001010001011 |
3 | 1201101112210212212121121112 |
4 | 2332222102001132022023 |
5 | 3204131100112041021 |
6 | 43511004404200535 |
7 | 2521411153261421 |
oct | 276522201361213 |
9 | 51345725777545 |
10 | 13102100112011 |
11 | 41a1629a40059 |
12 | 157733699914b |
13 | 7406a45c4991 |
14 | 334205d61111 |
15 | 17ac37e5bd5b |
hex | bea9205e28b |
13102100112011 has 4 divisors (see below), whose sum is σ = 13135102883472. Its totient is φ = 13069097340552.
The previous prime is 13102100111987. The next prime is 13102100112019. The reversal of 13102100112011 is 11021100120131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13102100112011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13102100112019) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16501385135 + ... + 16501385928.
It is an arithmetic number, because the mean of its divisors is an integer number (3283775720868).
Almost surely, 213102100112011 is an apocalyptic number.
13102100112011 is a deficient number, since it is larger than the sum of its proper divisors (33002771461).
13102100112011 is an equidigital number, since it uses as much as digits as its factorization.
13102100112011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33002771460.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 13102100112011 its reverse (11021100120131), we get a palindrome (24123200232142).
The spelling of 13102100112011 in words is "thirteen trillion, one hundred two billion, one hundred million, one hundred twelve thousand, eleven".
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