13102101213321 has 4 divisors (see below), whose sum is σ = 17469468284432. Its totient is φ = 8734734142212.

The previous prime is 13102101213319. The next prime is 13102101213329. The reversal of 13102101213321 is 12331210120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13102101213321 - 2¹ = 13102101213319 is a prime.

It is a super-3 number, since 3×13102101213321³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102101213329) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183683535551 + ... + 2183683535556.

It is an arithmetic number, because the mean of its divisors is an integer number (4367367071108).

Almost surely, 2^{13102101213321} is an apocalyptic number.

It is an amenable number.

13102101213321 is a deficient number, since it is larger than the sum of its proper divisors (4367367071111).

13102101213321 is an equidigital number, since it uses as much as digits as its factorization.

13102101213321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4367367071110.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 13102101213321 its reverse (12331210120131), we get a palindrome (25433311333452).

The spelling of 13102101213321 in words is "thirteen trillion, one hundred two billion, one hundred one million, two hundred thirteen thousand, three hundred twenty-one".