131021012421113 has 4 divisors (see below), whose sum is σ = 131021689351680. Its totient is φ = 131020335490548.

The previous prime is 131021012421107. The next prime is 131021012421161. The reversal of 131021012421113 is 311124210120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131021012421113 - 2¹⁴ = 131021012404729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131021012421413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 338174873 + ... + 338562086.

It is an arithmetic number, because the mean of its divisors is an integer number (32755422337920).

Almost surely, 2^{131021012421113} is an apocalyptic number.

It is an amenable number.

131021012421113 is a deficient number, since it is larger than the sum of its proper divisors (676930567).

131021012421113 is an equidigital number, since it uses as much as digits as its factorization.

131021012421113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 676930566.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 131021012421113 its reverse (311124210120131), we get a palindrome (442145222541244).

The spelling of 131021012421113 in words is "one hundred thirty-one trillion, twenty-one billion, twelve million, four hundred twenty-one thousand, one hundred thirteen".