Base | Representation |
---|---|
bin | 10011000100001110101… |
… | …010110001110000000011 |
3 | 11122020212212101002201122 |
4 | 103010032222301300003 |
5 | 132431303021321011 |
6 | 2441522551222455 |
7 | 163442152524044 |
oct | 23041652616003 |
9 | 4566785332648 |
10 | 1310211120131 |
11 | 465726024951 |
12 | 191b17077a2b |
13 | 96724763564 |
14 | 475b37868cb |
15 | 241355d73db |
hex | 1310eab1c03 |
1310211120131 has 4 divisors (see below), whose sum is σ = 1310227701552. Its totient is φ = 1310194538712.
The previous prime is 1310211120109. The next prime is 1310211120199.
1310211120131 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1310211120131 - 26 = 1310211120067 is a prime.
It is a super-2 number, since 2×13102111201312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1310211120731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8171615 + ... + 8330408.
It is an arithmetic number, because the mean of its divisors is an integer number (327556925388).
Almost surely, 21310211120131 is an apocalyptic number.
1310211120131 is a deficient number, since it is larger than the sum of its proper divisors (16581421).
1310211120131 is an equidigital number, since it uses as much as digits as its factorization.
1310211120131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16581420.
The product of its (nonzero) digits is 36, while the sum is 17.
The spelling of 1310211120131 in words is "one trillion, three hundred ten billion, two hundred eleven million, one hundred twenty thousand, one hundred thirty-one".
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