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13102120003 = 74621405049
BaseRepresentation
bin11000011001111001…
…00111110001000011
31020211002221122202211
430030330213301003
5203313120320003
610004035522551
7642453116410
oct141474476103
936732848684
1013102120003
115613894755
122657a59457
13130a5a843b
148c414d107
1551a3c496d
hex30cf27c43

13102120003 has 8 divisors (see below), whose sum is σ = 14977128800. Its totient is φ = 11227930560.

The previous prime is 13102119991. The next prime is 13102120007. The reversal of 13102120003 is 30002120131.

13102120003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13102120003 - 229 = 12565249091 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102120007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170178 + ... + 234871.

It is an arithmetic number, because the mean of its divisors is an integer number (1872141100).

Almost surely, 213102120003 is an apocalyptic number.

13102120003 is a deficient number, since it is larger than the sum of its proper divisors (1875008797).

13102120003 is an equidigital number, since it uses as much as digits as its factorization.

13102120003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 409677.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 13102120003 its reverse (30002120131), we get a palindrome (43104240134).

The spelling of 13102120003 in words is "thirteen billion, one hundred two million, one hundred twenty thousand, three".

Divisors: 1 7 4621 32347 405049 2835343 1871731429 13102120003