Base | Representation |
---|---|
bin | 11101110010100111000000… |
… | …101101001011011100101011 |
3 | 122011220111122102121100212102 |
4 | 131302213000231023130223 |
5 | 114133122414332331243 |
6 | 1142354151345404015 |
7 | 36411653510155520 |
oct | 3562470055133453 |
9 | 564814572540772 |
10 | 131021210433323 |
11 | 38824868634661 |
12 | 1284095633960b |
13 | 5815329c33992 |
14 | 244d663575147 |
15 | 1023267e779b8 |
hex | 7729c0b4b72b |
131021210433323 has 4 divisors (see below), whose sum is σ = 149738526209520. Its totient is φ = 112303894657128.
The previous prime is 131021210433287. The next prime is 131021210433331. The reversal of 131021210433323 is 323334012120131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131021210433323 - 26 = 131021210433259 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131021210432323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9358657888088 + ... + 9358657888101.
It is an arithmetic number, because the mean of its divisors is an integer number (37434631552380).
Almost surely, 2131021210433323 is an apocalyptic number.
131021210433323 is a deficient number, since it is larger than the sum of its proper divisors (18717315776197).
131021210433323 is an equidigital number, since it uses as much as digits as its factorization.
131021210433323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18717315776196.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 131021210433323 its reverse (323334012120131), we get a palindrome (454355222553454).
The spelling of 131021210433323 in words is "one hundred thirty-one trillion, twenty-one billion, two hundred ten million, four hundred thirty-three thousand, three hundred twenty-three".
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