1310213231113 has 4 divisors (see below), whose sum is σ = 1311379940368. Its totient is φ = 1309046521860.

The previous prime is 1310213231083. The next prime is 1310213231141. The reversal of 1310213231113 is 3111323120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310213231113 - 2¹³ = 1310213222921 is a prime.

It is a super-3 number, since 3×1310213231113³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310213201113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 583352943 + ... + 583355188.

It is an arithmetic number, because the mean of its divisors is an integer number (327844985092).

Almost surely, 2^{1310213231113} is an apocalyptic number.

It is an amenable number.

1310213231113 is a deficient number, since it is larger than the sum of its proper divisors (1166709255).

1310213231113 is a wasteful number, since it uses less digits than its factorization.

1310213231113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1166709254.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1310213231113 its reverse (3111323120131), we get a palindrome (4421536351244).

The spelling of 1310213231113 in words is "one trillion, three hundred ten billion, two hundred thirteen million, two hundred thirty-one thousand, one hundred thirteen".