Base | Representation |
---|---|
bin | 10011000100001110110… |
… | …110001100001101110011 |
3 | 11122020220002000002221212 |
4 | 103010032312030031303 |
5 | 132431304303041430 |
6 | 2441523135310335 |
7 | 163442220125036 |
oct | 23041666141563 |
9 | 4566802002855 |
10 | 1310214112115 |
11 | 465727788867 |
12 | 191b1807b3ab |
13 | 9672527036c |
14 | 475b3d2501d |
15 | 241359c8b95 |
hex | 1310ed8c373 |
1310214112115 has 8 divisors (see below), whose sum is σ = 1572263412480. Its totient is φ = 1048166971072.
The previous prime is 1310214112093. The next prime is 1310214112213. The reversal of 1310214112115 is 5112114120131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1310214112115 - 214 = 1310214095731 is a prime.
It is a super-2 number, since 2×13102141121152 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1486631 + ... + 2197839.
It is an arithmetic number, because the mean of its divisors is an integer number (196532926560).
Almost surely, 21310214112115 is an apocalyptic number.
1310214112115 is a deficient number, since it is larger than the sum of its proper divisors (262049300365).
1310214112115 is an equidigital number, since it uses as much as digits as its factorization.
1310214112115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1079661.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 1310214112115 its reverse (5112114120131), we get a palindrome (6422328232246).
The spelling of 1310214112115 in words is "one trillion, three hundred ten billion, two hundred fourteen million, one hundred twelve thousand, one hundred fifteen".
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