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1310214112115 = 5368447711209
BaseRepresentation
bin10011000100001110110…
…110001100001101110011
311122020220002000002221212
4103010032312030031303
5132431304303041430
62441523135310335
7163442220125036
oct23041666141563
94566802002855
101310214112115
11465727788867
12191b1807b3ab
139672527036c
14475b3d2501d
15241359c8b95
hex1310ed8c373

1310214112115 has 8 divisors (see below), whose sum is σ = 1572263412480. Its totient is φ = 1048166971072.

The previous prime is 1310214112093. The next prime is 1310214112213. The reversal of 1310214112115 is 5112114120131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310214112115 - 214 = 1310214095731 is a prime.

It is a super-2 number, since 2×13102141121152 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1486631 + ... + 2197839.

It is an arithmetic number, because the mean of its divisors is an integer number (196532926560).

Almost surely, 21310214112115 is an apocalyptic number.

1310214112115 is a deficient number, since it is larger than the sum of its proper divisors (262049300365).

1310214112115 is an equidigital number, since it uses as much as digits as its factorization.

1310214112115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1079661.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 1310214112115 its reverse (5112114120131), we get a palindrome (6422328232246).

The spelling of 1310214112115 in words is "one trillion, three hundred ten billion, two hundred fourteen million, one hundred twelve thousand, one hundred fifteen".

Divisors: 1 5 368447 711209 1842235 3556045 262042822423 1310214112115