1310214121 has 4 divisors (see below), whose sum is σ = 1332421200. Its totient is φ = 1288007044.

The previous prime is 1310214107. The next prime is 1310214133. The reversal of 1310214121 is 1214120131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310214121 - 2²³ = 1301825513 is a prime.

It is a super-2 number, since 2×1310214121² = 3433322085735605282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310214095 and 1310214104.

It is not an unprimeable number, because it can be changed into a prime (1310214151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11103451 + ... + 11103568.

It is an arithmetic number, because the mean of its divisors is an integer number (333105300).

Almost surely, 2^1310214121 is an apocalyptic number.

It is an amenable number.

1310214121 is a deficient number, since it is larger than the sum of its proper divisors (22207079).

1310214121 is an equidigital number, since it uses as much as digits as its factorization.

1310214121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22207078.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1310214121 is about 36196.8799898555. The cubic root of 1310214121 is about 1094.2437933349.

Adding to 1310214121 its reverse (1214120131), we get a palindrome (2524334252).

The spelling of 1310214121 in words is "one billion, three hundred ten million, two hundred fourteen thousand, one hundred twenty-one".