Base | Representation |
---|---|
bin | 11101110010100111001101… |
… | …111111000101110000011011 |
3 | 122011220112012221211201202111 |
4 | 131302213031333011300123 |
5 | 114133123343401414121 |
6 | 1142354225425013151 |
7 | 36411662154010531 |
oct | 3562471577056033 |
9 | 564815187751674 |
10 | 131021433232411 |
11 | 38824972379937 |
12 | 128409b8a841b7 |
13 | 5815364141467 |
14 | 244d684db0151 |
15 | 102327c7d72e1 |
hex | 7729cdfc5c1b |
131021433232411 has 16 divisors (see below), whose sum is σ = 137943238152960. Its totient is φ = 124102224735840.
The previous prime is 131021433232379. The next prime is 131021433232433. The reversal of 131021433232411 is 114232334120131.
It is a cyclic number.
It is not a de Polignac number, because 131021433232411 - 25 = 131021433232379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131021433232451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3463316266 + ... + 3463354096.
It is an arithmetic number, because the mean of its divisors is an integer number (8621452384560).
Almost surely, 2131021433232411 is an apocalyptic number.
131021433232411 is a deficient number, since it is larger than the sum of its proper divisors (6921804920549).
131021433232411 is a wasteful number, since it uses less digits than its factorization.
131021433232411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67314.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 131021433232411 its reverse (114232334120131), we get a palindrome (245253767352542).
The spelling of 131021433232411 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred thirty-three million, two hundred thirty-two thousand, four hundred eleven".
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