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1310222140041 = 3863506072669
BaseRepresentation
bin10011000100001111010…
…100110100001010001001
311122020220122002222012110
4103010033110310022021
5132431313331440131
62441524023332533
7163442345302053
oct23041724641211
94566818088173
101310222140041
11465731271311
12191b1a8b1149
1396726b21409
14475b50148d3
1524136562646
hex1310f534289

1310222140041 has 8 divisors (see below), whose sum is σ = 1748987147520. Its totient is φ = 872469279632.

The previous prime is 1310222139973. The next prime is 1310222140063. The reversal of 1310222140041 is 1400412220131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310222140041 - 29 = 1310222139529 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1310222144041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 253033746 + ... + 253038923.

It is an arithmetic number, because the mean of its divisors is an integer number (218623393440).

Almost surely, 21310222140041 is an apocalyptic number.

It is an amenable number.

1310222140041 is a deficient number, since it is larger than the sum of its proper divisors (438765007479).

1310222140041 is an equidigital number, since it uses as much as digits as its factorization.

1310222140041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 506073535.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1310222140041 its reverse (1400412220131), we get a palindrome (2710634360172).

The spelling of 1310222140041 in words is "one trillion, three hundred ten billion, two hundred twenty-two million, one hundred forty thousand, forty-one".

Divisors: 1 3 863 2589 506072669 1518218007 436740713347 1310222140041