Base | Representation |
---|---|
bin | 1011111010101001100111… |
… | …0100110110010111001011 |
3 | 1201101120011000012110222201 |
4 | 2332222121310312113023 |
5 | 3204131332120133003 |
6 | 43511025402101031 |
7 | 2521414333056325 |
oct | 276523164662713 |
9 | 51346130173881 |
10 | 13102231021003 |
11 | 41a1696922a03 |
12 | 15773727aa777 |
13 | 7406c576b117 |
14 | 3342194ba615 |
15 | 17ac446b9b1d |
hex | bea99d365cb |
13102231021003 has 4 divisors (see below), whose sum is σ = 13456345372960. Its totient is φ = 12748116669048.
The previous prime is 13102231021001. The next prime is 13102231021013. The reversal of 13102231021003 is 30012013220131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13102231021003 - 21 = 13102231021001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13102231021001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177057175923 + ... + 177057175996.
It is an arithmetic number, because the mean of its divisors is an integer number (3364086343240).
Almost surely, 213102231021003 is an apocalyptic number.
13102231021003 is a deficient number, since it is larger than the sum of its proper divisors (354114351957).
13102231021003 is an equidigital number, since it uses as much as digits as its factorization.
13102231021003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 354114351956.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13102231021003 its reverse (30012013220131), we get a palindrome (43114244241134).
The spelling of 13102231021003 in words is "thirteen trillion, one hundred two billion, two hundred thirty-one million, twenty-one thousand, three".
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