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131023313003 = 1111911210273
BaseRepresentation
bin111101000000110011…
…0010001100001101011
3110112012020110221011102
41322001212101201223
54121313432004003
6140105152152015
712315610533122
oct1720146214153
9415166427142
10131023313003
1150626276360
122148753860b
13c480bb509b
1464ad364ab9
15361caec588
hex1e8199186b

131023313003 has 4 divisors (see below), whose sum is σ = 142934523288. Its totient is φ = 119112102720.

The previous prime is 131023312991. The next prime is 131023313011. The reversal of 131023313003 is 300313320131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131023313003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131023373003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5955605126 + ... + 5955605147.

It is an arithmetic number, because the mean of its divisors is an integer number (35733630822).

Almost surely, 2131023313003 is an apocalyptic number.

131023313003 is a deficient number, since it is larger than the sum of its proper divisors (11911210285).

131023313003 is a wasteful number, since it uses less digits than its factorization.

131023313003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11911210284.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 131023313003 its reverse (300313320131), we get a palindrome (431336633134).

The spelling of 131023313003 in words is "one hundred thirty-one billion, twenty-three million, three hundred thirteen thousand, three".

Divisors: 1 11 11911210273 131023313003