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1310240113 = 71314398243
BaseRepresentation
bin100111000011000…
…1010110101110001
310101022110002112121
41032012022311301
510140410140423
6334002554241
744316600010
oct11606126561
93338402477
101310240113
11612661876
12306968981
1317b5b1c10
14c6028a77
157a06445d
hex4e18ad71

1310240113 has 8 divisors (see below), whose sum is σ = 1612603328. Its totient is φ = 1036673424.

The previous prime is 1310240101. The next prime is 1310240119. The reversal of 1310240113 is 3110420131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310240113 - 221 = 1308142961 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1310240119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7199031 + ... + 7199212.

It is an arithmetic number, because the mean of its divisors is an integer number (201575416).

Almost surely, 21310240113 is an apocalyptic number.

1310240113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1310240113 is a deficient number, since it is larger than the sum of its proper divisors (302363215).

1310240113 is a wasteful number, since it uses less digits than its factorization.

1310240113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14398263.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1310240113 is about 36197.2390245444. The cubic root of 1310240113 is about 1094.2510291488.

Adding to 1310240113 its reverse (3110420131), we get a palindrome (4420660244).

The spelling of 1310240113 in words is "one billion, three hundred ten million, two hundred forty thousand, one hundred thirteen".

Divisors: 1 7 13 91 14398243 100787701 187177159 1310240113