1310241113 has 4 divisors (see below), whose sum is σ = 1313267508. Its totient is φ = 1307214720.

The previous prime is 1310241109. The next prime is 1310241131. The reversal of 1310241113 is 3111420131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3111420131 = 1831 ⋅1699301.

It can be written as a sum of positive squares in 2 ways, for example, as 84400969 + 1225840144 = 9187^2 + 35012^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310241113 - 2² = 1310241109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310241091 and 1310241100.

It is not an unprimeable number, because it can be changed into a prime (1310241103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1512548 + ... + 1513413.

It is an arithmetic number, because the mean of its divisors is an integer number (328316877).

Almost surely, 2^1310241113 is an apocalyptic number.

It is an amenable number.

1310241113 is a deficient number, since it is larger than the sum of its proper divisors (3026395).

1310241113 is an equidigital number, since it uses as much as digits as its factorization.

1310241113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3026394.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1310241113 is about 36197.2528377500. The cubic root of 1310241113 is about 1094.2513075330.

Adding to 1310241113 its reverse (3111420131), we get a palindrome (4421661244).

The spelling of 1310241113 in words is "one billion, three hundred ten million, two hundred forty-one thousand, one hundred thirteen".