Base | Representation |
---|---|
bin | 10011000100010000101… |
… | …001011000110011100001 |
3 | 11122020222011211022222222 |
4 | 103010100221120303201 |
5 | 132431340020411431 |
6 | 2441530134440425 |
7 | 163443034610156 |
oct | 23042051306341 |
9 | 4566864738888 |
10 | 1310244310241 |
11 | 465742834099 |
12 | 191b26203115 |
13 | 9672b5b4589 |
14 | 475b7d4622d |
15 | 2413849157b |
hex | 13110a58ce1 |
1310244310241 has 8 divisors (see below), whose sum is σ = 1326061236864. Its totient is φ = 1294428118320.
The previous prime is 1310244310231. The next prime is 1310244310247. The reversal of 1310244310241 is 1420134420131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1310244310241 - 234 = 1293064441057 is a prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1310244310241.
It is not an unprimeable number, because it can be changed into a prime (1310244310247) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3967235 + ... + 4284791.
It is an arithmetic number, because the mean of its divisors is an integer number (165757654608).
Almost surely, 21310244310241 is an apocalyptic number.
It is an amenable number.
1310244310241 is a deficient number, since it is larger than the sum of its proper divisors (15816926623).
1310244310241 is an equidigital number, since it uses as much as digits as its factorization.
1310244310241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 367351.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 1310244310241 its reverse (1420134420131), we get a palindrome (2730378730372).
The spelling of 1310244310241 in words is "one trillion, three hundred ten billion, two hundred forty-four million, three hundred ten thousand, two hundred forty-one".
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