Search a number
-
+
131025323001 = 343675107667
BaseRepresentation
bin111101000000110110…
…1111100001111111001
3110112012101021001100210
41322001231330033321
54121314440314001
6140105303221333
712315633604146
oct1720155741771
9415171231323
10131025323001
1150627419511
1221488147849
13c481439c31
1464ad7293cd
15361cd97dd6
hex1e81b7c3f9

131025323001 has 4 divisors (see below), whose sum is σ = 174700430672. Its totient is φ = 87350215332.

The previous prime is 131025322991. The next prime is 131025323041. The reversal of 131025323001 is 100323520131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131025323001 - 25 = 131025322969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131025323041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21837553831 + ... + 21837553836.

It is an arithmetic number, because the mean of its divisors is an integer number (43675107668).

Almost surely, 2131025323001 is an apocalyptic number.

It is an amenable number.

131025323001 is a deficient number, since it is larger than the sum of its proper divisors (43675107671).

131025323001 is an equidigital number, since it uses as much as digits as its factorization.

131025323001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43675107670.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 131025323001 its reverse (100323520131), we get a palindrome (231348843132).

The spelling of 131025323001 in words is "one hundred thirty-one billion, twenty-five million, three hundred twenty-three thousand, one".

Divisors: 1 3 43675107667 131025323001