Base | Representation |
---|---|
bin | 11000011001111101… |
… | …11011110010111011 |
3 | 1020211011002110111102 |
4 | 30030332323302323 |
5 | 203313244220311 |
6 | 10004100522015 |
7 | 642461223212 |
oct | 141476736273 |
9 | 36734073442 |
10 | 13102726331 |
11 | 5614169252 |
12 | 26580b030b |
13 | 130a75b406 |
14 | 8c426a079 |
15 | 51a49443b |
hex | 30cfbbcbb |
13102726331 has 4 divisors (see below), whose sum is σ = 13422305064. Its totient is φ = 12783147600.
The previous prime is 13102726309. The next prime is 13102726333. The reversal of 13102726331 is 13362720131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13102726331 is a prime.
It is a super-3 number, since 3×131027263313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13102726294 and 13102726303.
It is not an unprimeable number, because it can be changed into a prime (13102726333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159789305 + ... + 159789386.
It is an arithmetic number, because the mean of its divisors is an integer number (3355576266).
Almost surely, 213102726331 is an apocalyptic number.
13102726331 is a deficient number, since it is larger than the sum of its proper divisors (319578733).
13102726331 is an equidigital number, since it uses as much as digits as its factorization.
13102726331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319578732.
The product of its (nonzero) digits is 4536, while the sum is 29.
The spelling of 13102726331 in words is "thirteen billion, one hundred two million, seven hundred twenty-six thousand, three hundred thirty-one".
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