1310300210113 has 4 divisors (see below), whose sum is σ = 1310626240560. Its totient is φ = 1309974179668.

The previous prime is 1310300210081. The next prime is 1310300210129. The reversal of 1310300210113 is 3110120030131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310300210113 - 2⁵ = 1310300210081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310300240113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163009195 + ... + 163017232.

It is an arithmetic number, because the mean of its divisors is an integer number (327656560140).

Almost surely, 2^{1310300210113} is an apocalyptic number.

It is an amenable number.

1310300210113 is a deficient number, since it is larger than the sum of its proper divisors (326030447).

1310300210113 is an equidigital number, since it uses as much as digits as its factorization.

1310300210113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 326030446.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1310300210113 its reverse (3110120030131), we get a palindrome (4420420240244).

The spelling of 1310300210113 in words is "one trillion, three hundred ten billion, three hundred million, two hundred ten thousand, one hundred thirteen".