131030121020131 has 4 divisors (see below), whose sum is σ = 131350488064600. Its totient is φ = 130709753975664.

The previous prime is 131030121020119. The next prime is 131030121020143. The reversal of 131030121020131 is 131020121030131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (131030121020119) and next prime (131030121020143).

It is a cyclic number.

It is not a de Polignac number, because 131030121020131 - 2⁷ = 131030121020003 is a prime.

It is a super-2 number, since 2×131030121020131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131030121020099 and 131030121020108.

It is not an unprimeable number, because it can be changed into a prime (131030121020111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160183521621 + ... + 160183522438.

It is an arithmetic number, because the mean of its divisors is an integer number (32837622016150).

Almost surely, 2^{131030121020131} is an apocalyptic number.

131030121020131 is a deficient number, since it is larger than the sum of its proper divisors (320367044469).

131030121020131 is an equidigital number, since it uses as much as digits as its factorization.

131030121020131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 320367044468.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 131030121020131 its reverse (131020121030131), we get a palindrome (262050242050262).

The spelling of 131030121020131 in words is "one hundred thirty-one trillion, thirty billion, one hundred twenty-one million, twenty thousand, one hundred thirty-one".