13103130222113 has 4 divisors (see below), whose sum is σ = 13103212500528. Its totient is φ = 13103047943700.

The previous prime is 13103130222109. The next prime is 13103130222121. The reversal of 13103130222113 is 31122203130131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13103130222113 - 2² = 13103130222109 is a prime.

It is a super-3 number, since 3×13103130222113³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13103130722113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40899863 + ... + 41218988.

It is an arithmetic number, because the mean of its divisors is an integer number (3275803125132).

Almost surely, 2^{13103130222113} is an apocalyptic number.

It is an amenable number.

13103130222113 is a deficient number, since it is larger than the sum of its proper divisors (82278415).

13103130222113 is an equidigital number, since it uses as much as digits as its factorization.

13103130222113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82278414.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13103130222113 its reverse (31122203130131), we get a palindrome (44225333352244).

The spelling of 13103130222113 in words is "thirteen trillion, one hundred three billion, one hundred thirty million, two hundred twenty-two thousand, one hundred thirteen".