1310313222131 has 4 divisors (see below), whose sum is σ = 1314943304472. Its totient is φ = 1305683139792.

The previous prime is 1310313222083. The next prime is 1310313222133. The reversal of 1310313222131 is 1312223130131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310313222131 - 2¹⁸ = 1310312959987 is a prime.

It is a super-2 number, since 2×1310313222131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310313222097 and 1310313222106.

It is not an unprimeable number, because it can be changed into a prime (1310313222133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2315040746 + ... + 2315041311.

It is an arithmetic number, because the mean of its divisors is an integer number (328735826118).

Almost surely, 2^{1310313222131} is an apocalyptic number.

1310313222131 is a deficient number, since it is larger than the sum of its proper divisors (4630082341).

1310313222131 is an equidigital number, since it uses as much as digits as its factorization.

1310313222131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4630082340.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1310313222131 its reverse (1312223130131), we get a palindrome (2622536352262).

The spelling of 1310313222131 in words is "one trillion, three hundred ten billion, three hundred thirteen million, two hundred twenty-two thousand, one hundred thirty-one".