1310319999947 has 4 divisors (see below), whose sum is σ = 1497508571376. Its totient is φ = 1123131428520.

The previous prime is 1310319999941. The next prime is 1310319999973. The reversal of 1310319999947 is 7499999130131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310319999947 - 2⁸ = 1310319999691 is a prime.

It is a super-2 number, since 2×1310319999947² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310319999941) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93594285704 + ... + 93594285717.

It is an arithmetic number, because the mean of its divisors is an integer number (374377142844).

Almost surely, 2^{1310319999947} is an apocalyptic number.

1310319999947 is a deficient number, since it is larger than the sum of its proper divisors (187188571429).

1310319999947 is an equidigital number, since it uses as much as digits as its factorization.

1310319999947 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 187188571428.

The product of its (nonzero) digits is 14880348, while the sum is 65.

The spelling of 1310319999947 in words is "one trillion, three hundred ten billion, three hundred nineteen million, nine hundred ninety-nine thousand, nine hundred forty-seven".