1310320000001 has 4 divisors (see below), whose sum is σ = 1310714321712. Its totient is φ = 1309925678292.

The previous prime is 1310319999997. The next prime is 1310320000021. The reversal of 1310320000001 is 1000000230131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310320000001 - 2² = 1310319999997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310320000021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 197155871 + ... + 197162516.

It is an arithmetic number, because the mean of its divisors is an integer number (327678580428).

Almost surely, 2^{1310320000001} is an apocalyptic number.

It is an amenable number.

1310320000001 is a deficient number, since it is larger than the sum of its proper divisors (394321711).

1310320000001 is an equidigital number, since it uses as much as digits as its factorization.

1310320000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 394321710.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 1310320000001 its reverse (1000000230131), we get a palindrome (2310320230132).

The spelling of 1310320000001 in words is "one trillion, three hundred ten billion, three hundred twenty million, one", and thus it is an aban number.