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13103310035 = 523910965113
BaseRepresentation
bin11000011010000010…
…01010010011010011
31020211012012010012002
430031001022103103
5203313421410120
610004121224215
7642466204034
oct141501122323
936735163162
1013103310035
115614527852
12265833206b
13130a903cba
148c437ca8b
1551a55c375
hex30d04a4d3

13103310035 has 8 divisors (see below), whose sum is σ = 15789764160. Its totient is φ = 10438786624.

The previous prime is 13103310023. The next prime is 13103310047. The reversal of 13103310035 is 53001330131.

It is an interprime number because it is at equal distance from previous prime (13103310023) and next prime (13103310047).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13103310035 - 216 = 13103244499 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13103309989 and 13103310016.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5481362 + ... + 5483751.

It is an arithmetic number, because the mean of its divisors is an integer number (1973720520).

Almost surely, 213103310035 is an apocalyptic number.

13103310035 is a deficient number, since it is larger than the sum of its proper divisors (2686454125).

13103310035 is a wasteful number, since it uses less digits than its factorization.

13103310035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10965357.

The product of its (nonzero) digits is 405, while the sum is 20.

Adding to 13103310035 its reverse (53001330131), we get a palindrome (66104640166).

The spelling of 13103310035 in words is "thirteen billion, one hundred three million, three hundred ten thousand, thirty-five".

Divisors: 1 5 239 1195 10965113 54825565 2620662007 13103310035