Base | Representation |
---|---|
bin | 111101000001001011… |
… | …1101011000100001011 |
3 | 110112020010211211202121 |
4 | 1322002113223010023 |
5 | 4121330240401132 |
6 | 140110333512111 |
7 | 12316125566212 |
oct | 1720227530413 |
9 | 415203754677 |
10 | 131036262667 |
11 | 50632610662 |
12 | 2148b942637 |
13 | c48379a3cb |
14 | 64b0d76079 |
15 | 361dd09497 |
hex | 1e825eb10b |
131036262667 has 4 divisors (see below), whose sum is σ = 138744278136. Its totient is φ = 123328247200.
The previous prime is 131036262661. The next prime is 131036262671. The reversal of 131036262667 is 766262630131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 766262630131 = 346373 ⋅2212247.
It is a cyclic number.
It is not a de Polignac number, because 131036262667 - 23 = 131036262659 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131036262661) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3854007709 + ... + 3854007742.
It is an arithmetic number, because the mean of its divisors is an integer number (34686069534).
Almost surely, 2131036262667 is an apocalyptic number.
131036262667 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
131036262667 is a deficient number, since it is larger than the sum of its proper divisors (7708015469).
131036262667 is an equidigital number, since it uses as much as digits as its factorization.
131036262667 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7708015468.
The product of its (nonzero) digits is 326592, while the sum is 43.
Adding to 131036262667 its reverse (766262630131), we get a palindrome (897298892798).
The spelling of 131036262667 in words is "one hundred thirty-one billion, thirty-six million, two hundred sixty-two thousand, six hundred sixty-seven".
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