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13104033113 = 181376719219
BaseRepresentation
bin11000011010000111…
…11010110101011001
31020211020112212001202
430031003322311121
5203314113024423
610004144523545
7642505305113
oct141503726531
936736485052
1013104033113
115614981036
1226586205b5
13130aac8162
148c44ca3b3
1551a651728
hex30d0fad59

13104033113 has 8 divisors (see below), whose sum is σ = 13180614720. Its totient is φ = 13027497840.

The previous prime is 13104033091. The next prime is 13104033127. The reversal of 13104033113 is 31133040131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13104033113 - 26 = 13104033049 is a prime.

It is a super-3 number, since 3×131040331133 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104033193) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 672218 + ... + 691436.

It is an arithmetic number, because the mean of its divisors is an integer number (1647576840).

Almost surely, 213104033113 is an apocalyptic number.

It is an amenable number.

13104033113 is a deficient number, since it is larger than the sum of its proper divisors (76581607).

13104033113 is a wasteful number, since it uses less digits than its factorization.

13104033113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23167.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 13104033113 its reverse (31133040131), we get a palindrome (44237073244).

The spelling of 13104033113 in words is "thirteen billion, one hundred four million, thirty-three thousand, one hundred thirteen".

Divisors: 1 181 3767 19219 681827 3478639 72397973 13104033113