131040400033 has 4 divisors (see below), whose sum is σ = 131041295428. Its totient is φ = 131039504640.

The previous prime is 131040400013. The next prime is 131040400061. The reversal of 131040400033 is 330004040131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 330004040131 = 324557 ⋅1016783.

It can be written as a sum of positive squares in 2 ways, for example, as 86243830929 + 44796569104 = 293673^2 + 211652^2 .

It is a cyclic number.

It is not a de Polignac number, because 131040400033 - 2²¹ = 131038302881 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131040400013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171288 + ... + 539833.

It is an arithmetic number, because the mean of its divisors is an integer number (32760323857).

Almost surely, 2^131040400033 is an apocalyptic number.

It is an amenable number.

131040400033 is a deficient number, since it is larger than the sum of its proper divisors (895395).

131040400033 is an equidigital number, since it uses as much as digits as its factorization.

131040400033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 895394.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 131040400033 its reverse (330004040131), we get a palindrome (461044440164).

The spelling of 131040400033 in words is "one hundred thirty-one billion, forty million, four hundred thousand, thirty-three".