13104203304433 has 4 divisors (see below), whose sum is σ = 13136882116068. Its totient is φ = 13071524492800.

The previous prime is 13104203304391. The next prime is 13104203304481. The reversal of 13104203304433 is 33440330240131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12846253083889 + 257950220544 = 3584167^2 + 507888^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104203304433 - 2⁹ = 13104203303921 is a prime.

It is a super-3 number, since 3×13104203304433³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104203304395 and 13104203304404.

It is not an unprimeable number, because it can be changed into a prime (13104203304133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16339405216 + ... + 16339406017.

It is an arithmetic number, because the mean of its divisors is an integer number (3284220529017).

Almost surely, 2^{13104203304433} is an apocalyptic number.

It is an amenable number.

13104203304433 is a deficient number, since it is larger than the sum of its proper divisors (32678811635).

13104203304433 is an equidigital number, since it uses as much as digits as its factorization.

13104203304433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32678811634.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 13104203304433 its reverse (33440330240131), we get a palindrome (46544533544564).

The spelling of 13104203304433 in words is "thirteen trillion, one hundred four billion, two hundred three million, three hundred four thousand, four hundred thirty-three".